8a^2+8a=-5+14

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Solution for 8a^2+8a=-5+14 equation:



8a^2+8a=-5+14
We move all terms to the left:
8a^2+8a-(-5+14)=0
We add all the numbers together, and all the variables
8a^2+8a-9=0
a = 8; b = 8; c = -9;
Δ = b2-4ac
Δ = 82-4·8·(-9)
Δ = 352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{352}=\sqrt{16*22}=\sqrt{16}*\sqrt{22}=4\sqrt{22}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{22}}{2*8}=\frac{-8-4\sqrt{22}}{16} $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{22}}{2*8}=\frac{-8+4\sqrt{22}}{16} $

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